# How do you find slope of the line that contains (1,6) and (10, -9)?

Mar 18, 2018

Slope $= - \frac{5}{3}$

#### Explanation:

Recall the slope formula.

The given points are (1,6) and (10, -9)

comparing with $\left({x}_{1} , {y}_{1}\right) \mathmr{and} \left({x}_{2} , {y}_{2}\right)$
${x}_{1} = 1$color(white)(dddddddddddddd${x}_{2} = 10$
${y}_{1} = 6$color(white)(dddddddddddddd${y}_{2} = - 9$

$m = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

$m = \frac{- 9 - 6}{10 - 1}$

$m = \frac{- 15}{9}$

Slope= $- \frac{15}{9} = - \frac{5}{3}$

Mar 18, 2018

$m = - \frac{5}{3}$

#### Explanation:

$\text{Slope } \left(m\right) = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

Here , ${x}_{1} = 1$

${y}_{1} = 6$

${x}_{2} = 10$

${y}_{2} = - 9$

$\implies m = \frac{- 9 - 6}{10 - 1}$

$\implies m = - \frac{15}{9}$

$\implies m = - \frac{5}{3}$