How do you find the amplitude and period for #y=1/2cosx-3#?

1 Answer
Jul 24, 2017

#1/2,2pi#

Explanation:

#"the standard form of the "color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b," vertical shift "=d#

#"here "a=1/2,b=1,c=0,d=-3#

#rArr"amplitude "=|1/2|=1/2," period "=2pi#