How do you find the amplitude and period for #y=-2sin(x+pi/2)#?
1 Answer
Aug 12, 2016
amplitude = 2
period
Explanation:
For the standard
#color(blue)"sine function"#
#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))# The amplitude = |a| , period
#=(2pi)/b# phase shift =
#-c/b" and "# vertical shift = dhere a = -2 , b = 1 , c
#=pi/2" and d = 0"# Hence amplitude = |-2| = 2 and period
#=(2pi)/1=2pi#