# How do you find the amplitude and period for y=-2sin(x+pi/2)?

Aug 12, 2016

amplitude = 2
period $= 2 \pi$

#### Explanation:

For the standard $\textcolor{b l u e}{\text{sine function}}$

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y = a \sin \left(b x + c\right) + d} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

The amplitude = |a| , period $= \frac{2 \pi}{b}$

phase shift = $- \frac{c}{b} \text{ and }$ vertical shift = d

here a = -2 , b = 1 , c $= \frac{\pi}{2} \text{ and d = 0}$

Hence amplitude = |-2| = 2 and period $= \frac{2 \pi}{1} = 2 \pi$