How do you find the amplitude and period for y=-2sin(x+pi/2)?

1 Answer
Aug 12, 2016

amplitude = 2
period =2pi

Explanation:

For the standard color(blue)"sine function"

color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))

The amplitude = |a| , period =(2pi)/b

phase shift = -c/b" and " vertical shift = d

here a = -2 , b = 1 , c =pi/2" and d = 0"

Hence amplitude = |-2| = 2 and period =(2pi)/1=2pi