How do you find the amplitude and period for #y=cos2x+1#?

1 Answer
Jim G.
Dec 4, 2016

#"amplitude " =1" and period "=pi#

Explanation:

The standard form of the #color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|,"period " =(2pi)/b#

#"phase shift " =-c/b" and " d " is the vertical shift"#

#"Here " a=1,b=2,c=0" and " d=1#

#rArr"amplitude " =|1|=1" and period " =(2pi)/2=pi#

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