# How do you find the amplitude and period of a function y = (1/2) sin ((x/3)-π)?

Nov 4, 2016

Amplitude is $\frac{1}{2}$ and period is $6 \pi$

#### Explanation:

In $y = a \sin \left(b x + c\right)$,

amplitude is $a$, period is $\frac{2 \pi}{b}$ and phase shift is $- \frac{c}{b}$.

In the function $y = \frac{1}{2} \sin \left(\frac{x}{3} - \pi\right)$

Amplitude is $\frac{1}{2}$ and period is $\frac{2 \pi}{\frac{1}{3}} = 6 \pi$