# How do you find the amplitude and period of a function y=3sin(1/3x+ pi/2)-2?

##### 1 Answer
Feb 28, 2016

3 and 6$\pi$.

#### Explanation:

The amplitude and period of the sine wave y = a sin (bx + c ) + d are a and 2$\pi$/b.
Here, one full wave wave passes through
( 0, 1 ), ( $\pi$ , $-$1/2 ), (2$\pi$, $-$7/2), ( 3$\pi$, $-$5), (4$\pi$, $-$7/2 ), (5$\pi$, $-$1/2 ) and (6$\pi$, 1 ).
Max y = 1 and min y = $-$5.
The wave is contained between the tangents y =1 and y = $-$5