How do you find the amplitude and period of a function #y=-.4 sin (10x+pi/2)#?

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Answer 1 · 2016-07-01T14:41:43

Amplitude #=0.4#
Period #=pi/5#

For a given sine function #y=A sin (Bx+C)#

Amplitude #=abs(A)#
Period #=(2pi)/B#

Solution :

#y=-0.4 sin (10x +pi/2)#

Amplitude #=abs(-0.4)=0.4#

Period #(2pi)/abs(B)=(2pi)/10=pi/5#

God bless....I hope the explanation is useful.