# How do you find the amplitude and period of a function y=-.4 sin (10x+pi/2)?

Amplitude $= 0.4$
Period $= \frac{\pi}{5}$

#### Explanation:

For a given sine function $y = A \sin \left(B x + C\right)$

Amplitude $= \left\mid A \right\mid$
Period $= \frac{2 \pi}{B}$

Solution :

$y = - 0.4 \sin \left(10 x + \frac{\pi}{2}\right)$

Amplitude $= \left\mid - 0.4 \right\mid = 0.4$

Period $\frac{2 \pi}{\left\mid B \right\mid} = \frac{2 \pi}{10} = \frac{\pi}{5}$

God bless....I hope the explanation is useful.