# How do you find the amplitude and period of a function y=4sin(2x)+1 ?

The amplitude is 4 and the period is $\pi$. The phase change (if you cared) is (0, 1)
The equation can be written as $a \sin \left(b \left(x - c\right)\right) + d$. For sin and cos (but not tan) $| a |$ is the amplitude, $\frac{2 \pi}{|} b |$ is the period, and $c$ and $d$ are the phase shifts. $c$ is the phase shift to the right (positive $x$ direction) and $d$ is the phase shift up (positive $y$ direction). Hope this helps!