# How do you find the amplitude and period of a function y = 5+3sinx?

The amplitude is 3 and the period is 2$\pi$. (The phase shift is (0, 5) if you wanted to know).
The equation can be written as asin(b(x−c))+d (or in your case $d + a \sin \left(b \left(x - c\right)\right)$. For sin and cos (but not tan) $| a |$ is the amplitude, (2π)/|b| is the period, and $c$ and $d$ are the phase shifts. $c$ is the phase shift to the right (positive $x$ direction) and $d$ is the phase shift up (positive $y$ direction). Hope this helps!