# How do you find the amplitude and period of a function y = sin 2π/3 (x-6) ?

Mar 20, 2016

Amplitude is 1 and period is $\frac{2 \pi}{\left(2 \frac{\pi}{3}\right)}$ = 3 radians.

#### Explanation:

The amplitude and the period for the sine wave

y = a sin (bx + c) are

a and $2 \frac{\pi}{b}$.

Here, a = 1 and b = $2 \frac{\pi}{3}$.