How do you find the amplitude and period of a function #y= sin(2pix/23)#?

1 Answer
Feb 14, 2018

The amplitude is #1# and the period is #23#.

Explanation:

In the general formula

#y=asin(b(x-c))+d#,

#a# is the amplitude and #b# is the horizontal compression. To calculate the period, divide #2pi# by the #b# value.

Here's our equation:

#y=sin((2pi)/23x)#

Our amplitude is #1# because that it the #a# value.

Here's the calculation for the period:

#"period"=(2pi)/b=(2pi)/((2pi)/23)=color(red)(cancel(color(black)(2pi)))*23/(color(red)(cancel(color(black)(2pi))))=23#