# How do you find the amplitude and period of y=1/2sin2theta?

Jan 25, 2017

$\text{amplitude " =1/2," period} = \pi$

#### Explanation:

The standard form of the $\textcolor{b l u e}{\text{sine function}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = a \sin \left(b x + c\right) + d} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\text{where amplitude "=|a|," period } = \frac{2 \pi}{b}$

$\text{phase shift "=-c/b" and vertical shift } = d$

$\text{here } a = \frac{1}{2} , b = 2 , c = 0 , d = 0$

$\Rightarrow \text{amplitude "=|1/2|=1/2," period } = \frac{2 \pi}{2} = \pi$