# How do you find the amplitude and period of y=2cottheta?

Jun 20, 2018

As below.

#### Explanation:

$y = A \sin \left(B x - C\right) + D$

$y = 2 \cot \theta$

$A = 2 , B = 1 , C = D = 0$

$\text{Amplitude of cotangent function is " color(brown)(" NONE}$

$\text{Period } = \frac{\pi}{|} B | = \pi$

$\text{Phase Shift } = - \frac{C}{B} = 0$

$\text{Vertical Shift } = D = 0$

graph{2 cot x [-10, 10, -5, 5]}