How do you find the amplitude and period of y=2csc(1/2t)?

Nov 7, 2017

Amplitude = 2, Period =$4 \pi$

Explanation:

$y = 2 \csc \left(\frac{1}{2}\right) t$

In this equation, $a = 2 , b = \frac{1}{2}$

Amplitude $A = 2$

Period = $\frac{2 \pi}{|} b |$

Period $= \frac{2 \pi}{\frac{1}{2}} = 4 \pi$