Question

How do you find the amplitude and period of `y=2csc(1/2t)`?

Answer 1

Amplitude = 2, Period =`4pi`

Explanation:

`y=2csc(1/2)t`

In this equation, `a = 2, b = 1/2`

Amplitude `A = 2`

Period = `(2pi)/|b|`

Period `= (2pi)/(1/2) = 4pi`