Question

How do you find the amplitude and period of `y=2sec(1/4t)`?

Answer 1

Amplitude = None, Period `= 8pi`

Explanation:

Standard form `y = a sec(bx - c) + d`

Given equation is `y = 2 sec(1/4)t`

`"Amplitude = None"`

`"Period" = (2pi)/|b| = (2pi) / (1/4) = 8pi`

# graph{2 sec((1/4)x) [-10, 10, -5, 5]}