How do you find the amplitude and period of y=2sec(1/4t)?

Mar 18, 2018

Amplitude = None, Period $= 8 \pi$

Explanation:

Standard form $y = a \sec \left(b x - c\right) + d$

Given equation is $y = 2 \sec \left(\frac{1}{4}\right) t$

$\text{Amplitude = None}$

$\text{Period} = \frac{2 \pi}{|} b | = \frac{2 \pi}{\frac{1}{4}} = 8 \pi$

# graph{2 sec((1/4)x) [-10, 10, -5, 5]}