# How do you find the amplitude and period of y=2sin(4t)?

Nov 3, 2016

$A = 2$
$T = \frac{\pi}{2}$

#### Explanation:

if $y = 2 \sin \left(4 t\right)$

and $y = A \sin \left(\omega x\right)$
$A m p l i t u \mathrm{de} = \left\mid A \right\mid$
$T \left(p e r i o d\right) = \frac{2 \pi}{\omega}$, $\omega > 0$

then
$\left\mid A \right\mid = \left\mid 2 \right\mid$
and $T = \frac{2 \pi}{4} = \frac{\pi}{2}$