How do you find the amplitude and period of #y=2sintheta#?

1 Answer
Jan 10, 2017

I found:
Amplitude#=2#;
Period#=2pi#

Explanation:

The amplitude is given by the number in front of the sine function, #2# in this case. This means that your function goes from #+2# to #-2#;
The period is a bit more tricky....you need the number that is multiplying the argument of the sine, #1# in this case, and divide #2pi# by this number:
#"period"=(2pi)/1=2pi#

Let us see these values graphically:
graph{2*sin(x) [-10, 10, -5, 5]}