How do you find the amplitude and period of #y=2sintheta#?

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Gió Share
Jan 10, 2017

Answer:

I found:
Amplitude#=2#;
Period#=2pi#

Explanation:

The amplitude is given by the number in front of the sine function, #2# in this case. This means that your function goes from #+2# to #-2#;
The period is a bit more tricky....you need the number that is multiplying the argument of the sine, #1# in this case, and divide #2pi# by this number:
#"period"=(2pi)/1=2pi#

Let us see these values graphically:
graph{2*sin(x) [-10, 10, -5, 5]}

Was this helpful? Let the contributor know!
1500