# How do you find the amplitude and period of y=3sectheta?

Amp: $3$.
Period: $\pi$.
$y = \textcolor{g r e e n}{3} \sec \textcolor{red}{1} \theta$
$\textcolor{g r e e n}{A m p}$: There aren't amplitudes for secants or cosecants, but the closest thing is $3$. Amplitude only applies for sin and cos.
$\textcolor{red}{P e r i o d}$: To find the period for sec and csc, we divide the leading coefficient of $\theta$, which in this case is $1$, by $\pi$, which gives us $\frac{\pi}{1}$ or $\pi$.