# How do you find the amplitude and period of y = 3sin2x-(pi/2)?

Jul 25, 2018

As below. graph{3 sin (2x) - pi/2 [-10, 10, -5, 5]}

#### Explanation:

Standard form of sine function is $y = A \sin \left(B x - C\right) + D$

Given: $y = 3 \sin 2 x - \frac{\pi}{2}$

$A = 3 , B = 2 , C = 0 , D = \frac{\pi}{2}$

Amplitude $= | A | = 3$

Period $= \frac{2 \pi}{|} B | = \frac{2 \pi}{2} = \pi$

Phase Shift $= - \frac{C}{B} = 0$

Vertical Shift $= D = - \left(\frac{\pi}{2}\right)$