# How do you find the amplitude and period of y=5sin(2/3theta)?

Jul 19, 2017

$A = 5$ and $T = 3 \pi$

#### Explanation:

A function :

y=Asinωθ has amplitude equal to $A$ and period equal to

T=(2pi)/ω

so the amplitude of the function y=5sin(2/3θ) is $A = 5$

and the period is $T = \frac{2 \pi}{\frac{2}{3}} = 3 \pi$