How do you find the amplitude and period of #y=cos(1/2theta)#?

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Answer 1 · 2018-03-04T02:02:31

Amplitude # = a = color(red)(1#

Period # = (2pi) / |b| =color(green)( 4pi#

#y = cos (theta/2)#

Standard form of equation for cosine is

#y = a cos (bx - c) + d#

Amplitude # = a = 1#

Period # = (2pi) / |b| = (2pi) / |1/2| = 4pi#

graph{cos (x/2) [-10, 10, -5, 5]}