How do you find the amplitude and period of #y=tan(1/2theta)#?

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Answer 1 · 2018-03-17T10:25:10

Amplitude = None, Perod = #2pi#

Standard for of equation to find amplitude, period is

#y = a tan (bx -c) + d#

Given equation is #y = tan (theta/2)#

#"Amplitude"# # =# #"none"#

#"Period" = (2pi) / |b| = (pi) / (1/2) = 2pi#

#"Phase Shift" # = #-c / b = 0 / (1/2) = 0# #color(white)(aaa) (0# # "to the right")#

graph{tan (x/2) [-10, 10, -5, 5]}