# How do you find the amplitude and period of y=tan(1/2theta)?

Mar 17, 2018

Amplitude = None, Perod = $2 \pi$

#### Explanation:

Standard for of equation to find amplitude, period is

$y = a \tan \left(b x - c\right) + d$

Given equation is $y = \tan \left(\frac{\theta}{2}\right)$

$\text{Amplitude}$ $=$ $\text{none}$

$\text{Period} = \frac{2 \pi}{|} b | = \frac{\pi}{\frac{1}{2}} = 2 \pi$

$\text{Phase Shift}$ = $- \frac{c}{b} = \frac{0}{\frac{1}{2}} = 0$ color(white)(aaa) (0  "to the right")

graph{tan (x/2) [-10, 10, -5, 5]}