# How do you find the amplitude, period and graph y=3csc(1/2theta)?

Oct 15, 2017

Amplitude none
Period $= \frac{2 \pi}{\frac{1}{2}} = 4 \pi$
Phase shift $= 0$
Vertical shift $= 0$

graph{3csc(x/2) [-10, 10, -5, 5]}

#### Explanation:

$y = 3 \csc \left(\frac{\theta}{2}\right)$

Standard form $a \csc \left(b x - c\right) + d$

Since the graph of the function csc does not have a maximum or minimum value, there can be no value for the amplitude.

Period $= \ast \frac{2 \pi}{b} \ast$

Phase shift $= \ast \frac{c}{b} \ast$

Vertical shift $= \ast d \ast$

Amplitude none
Period $= \frac{2 \pi}{\frac{1}{2}} = 4 \pi$
Phase shift $= 0$
Vertical shift $= 0$