# How do you find the amplitude, period and phase shift for y=1/2tantheta+1?

Jun 20, 2018

As below.

#### Explanation:

$y = A \tan \left(B x - C\right) + D$ is the standard form.

$y = \left(\frac{1}{2}\right) \tan \theta + 1$

$A m p l i t u \mathrm{de} = | A | = | \left(\frac{1}{2}\right) | = \frac{1}{2}$

$\text{Period } = \frac{\pi}{|} B | = \frac{\pi}{1} = \pi$

$\text{Phase Shift } = - \frac{C}{B} = 0$

$\text{Vertical Shift } = D = 1$

graph{(1/2) tan x + 1 [-10, 10, -5, 5]}