How do you find the amplitude, period and phase shift for #y=sin(theta-180^circ)#?

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Answer 1 · 2018-07-13T01:48:55

As below.

Standard form a sine function is #y = A sin (Bx - C) + D#

#"Given " y = sin (theta - 180^@) = sin (theta - pi^c)#

#A = 1, B = 1, C = pi, D = 0#

#Amplitude = |A| = 1#

#"Period ' = (2pi) / |B| = (2pi)#

#"Phase Shift " = -C / B = -pi / 1 = -pi, " "color(crimson)( pi " to the LEFT"#

#"Vertical Shift " = D = 0#

graph{sin(x - pi) [-10, 10, -5, 5]}