# How do you find the amplitude, period and phase shift for y=tantheta+1/2?

##### 1 Answer
Nov 23, 2017

Amplitude = 1, Period = $\pi$, Phase shift = 2

#### Explanation:

Standard form of equation is
$y = a \tan \left(b x - c\right) + d$
Where Amplitude = a, Period = $\left(\frac{\pi}{|} b |\right)$, Phase shift = $\frac{c}{b}$

Given equation is $y = \tan \left(\theta + \left(\frac{1}{2}\right)\right)$

graph{tan(x + (1/2)) [-10, 10, -5, 5]}

Amplitude = 1, Period =$\left(\frac{\pi}{1}\right) = \pi$ & Phase shift = 1/(1/2) = 2#