# How do you find the amplitude, period and phase shift of y= -3 sin (2x + pi/2)?

May 13, 2016

$3 , \pi \mathmr{and} \frac{\pi}{2}$

#### Explanation:

The standard form of the sine wave function is

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{y = a \sin \left(b x + c\right) + d} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

where |a| is the amplitude , period$= \frac{2 \pi}{b}$

c , represents the phase-shift and d , the vertical shift.

here amplitude = |-3| = 3 , period$= \frac{2 \pi}{2} = \pi$

phase-shift$= \frac{\pi}{2}$and vertical shift = 0