# How do you find the amplitude, period, and shift for y= -4 + 3 sin (x+ pi/3)?

Oct 3, 2016

$A = 3$
$B = 1 , P = \frac{2 \pi}{1} = 2 \pi$
$C = - 4$
$D = - \frac{\pi}{3}$

#### Explanation:

General sinusoidal equation is $y = C + A \cos \left(x - D\right)$
$\left\mid A \right\mid$- is the amplitude
$B$- is the number of cycles and therefore the period is $P = \frac{2 \pi}{B}$
$C$- is the shift in y
$D$- is the shift in x
Therefore from our equation we have
$A = 3$
$B = 1 , P = \frac{2 \pi}{1} = 2 \pi$
$C = - 4$
$D = - \frac{\pi}{3}$