# How do you find the amplitude, period, phase shift given y=sin(2pix-pi)?

Jan 8, 2018

Amplitude is $1$ , period is $1$ and phase shift is $\frac{1}{2}$

#### Explanation:

The sinusidal function is $y = A \sin \left(B x + C\right) + D$ where $A$ is

amplitude , period is $\frac{2 \pi}{|} B |$ , phase shift is $- \frac{C}{|} B |$, vertical

shift is D ; y= sin(2pi*x-pi) or y= 1*sin(2pi*x-pi)+0

$\therefore A = 1 , B = 2 \pi , C = - \pi , D = 0$

Therefore amplitude is $1$ , period is $\frac{2 \pi}{|} B | = \frac{2 \pi}{2 \pi} = 1$

phase shift is $- \frac{C}{|} B | = - \frac{- \pi}{2 \pi} = \frac{1}{2}$

graph{sin(2pix-pi) [-10, 10, -5, 5]} [Ans]