# How do you find the amplitude, period, vertical and phase shift and graph y=1/2sintheta+1/2?

Jul 13, 2018

As below.

#### Explanation:

$y = \left(\frac{1}{2}\right) \sin \left(\theta\right) + \frac{1}{2}$

Standard form of a sine function is $y = A \sin \left(B x - C\right) + D$

$A = \frac{1}{2} , B = 1 , C = 0 , D = \frac{1}{2}$

$A m p l i t u \mathrm{de} = | A | = \frac{1}{2}$

$\text{Period } = \frac{2 \pi}{|} B | = 2 \pi$

"Phase Shift ' = -C / B = 0

$\text{Vertical shift } = D = \frac{1}{2}$

graph{(1/2) sin x + 1/2 [-10, 10, -5, 5]}