Question

How do you find the amplitude, phase shift and period of `Y = – 23 Cos (3X – π / 6) + 8`?

Answer 1

amplitude = 23 , #"period"= (2pi)/3" and phase shift "= (-pi/6)#

Explanation:

The standard form of the function is :

y = acos (bx + c ) + d

where |a| = amplitude , period = `(2pi)/b`

c = phase shift and d , a translation `((0),(d))`

here amplitude = |-23|= 23 , period`= (2pi)/3`

phase shift =`(-pi/6) " move to the right "`