# How do you find the amplitude, phase shift and period of Y = – 23 Cos (3X – π / 6) + 8?

Mar 11, 2016

amplitude = 23 , "period"= (2pi)/3" and phase shift "= (-pi/6)

#### Explanation:

The standard form of the function is :

y = acos (bx + c ) + d

where |a| = amplitude , period = $\frac{2 \pi}{b}$

c = phase shift and d , a translation $\left(\begin{matrix}0 \\ d\end{matrix}\right)$

here amplitude = |-23|= 23 , period$= \frac{2 \pi}{3}$

phase shift =$\left(- \frac{\pi}{6}\right) \text{ move to the right }$