# How do you find the antiderivative of int (x^2+1)^2 dx?

$\int {\left({x}^{2} + 1\right)}^{2} \mathrm{dx} = {x}^{5} / 5 + 2 {x}^{3} / 3 + x + c$
$\int {\left({x}^{2} + 1\right)}^{2} \mathrm{dx} =$
$\int \left({x}^{4} + 2 {x}^{2} + 1\right) \mathrm{dx} =$
${x}^{5} / 5 + 2 {x}^{3} / 3 + x + c$ , $c$$\in$$\mathbb{R}$