# How do you find the antiderivative of (x-6)^2?

$\frac{1}{3} {x}^{3} - 6 {x}^{2} + 36 x + C$
${\left(x - 6\right)}^{2}$= ${x}^{2} - 12 x + 36$
int_${x}^{2} - 12 x + 36$ dx = $\frac{1}{3} {x}^{3} - 6 {x}^{2} + 36 x + C$
Remember power rule is int_$a {x}^{n}$ = $\frac{a {x}^{n + 1}}{n + 1}$