# How do you find the area of a rhombus with diagonal lengths of 12 cm and 8 cm?

May 1, 2018

$48 c {m}^{2}$

#### Explanation:

The area of a rhombus is $\frac{1}{2}$ (product of diagonals)

Thus the area is $\frac{1}{2} \left(12 \times 8\right) = 6 \times 8$
$= 48 c {m}^{2}$

May 1, 2018

$A = 48 {\left(c m\right)}^{2}$

#### Explanation:

The area of a rhombus is $A = \frac{1}{2} \left({L}_{1}\right) \left({L}_{2}\right)$ where ${L}_{1}$ and ${L}_{2}$ are diagonals of the rhombus. Inputting values:
$A = \frac{1}{2} \left(8 c m\right) \left(12 c m\right)$
$A = \left(4 c m\right) \left(12 c m\right)$
$A = 48 {\left(c m\right)}^{2}$