Question

How do you find the area of a triangle whose vertices are (2,-2), (8,5), (6,-10)?

Answer 1

I fount `38` ua

Explanation:

I would use a matrix method involving the Determinant of a square matrix.
The area of the triangle is `+-1/2` the determinant of the matrix formed by the coordinates of the vertecies of the triangle and a column of `1`, i.e.:
Area`=+-1/2*det` `((2,-2,1),(8,5,1),(6,-10,1))=`
`=+-1/2(-72)=` changing sign through `+-` you get:
Area`=76/2=38` units of area