# How do you find the area of triangle ABC given a=2, b=3, c=4?

Jul 23, 2017

The area is $= 2.9 {u}^{2}$

#### Explanation:

We apply Heron's formula

$a r e a = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$

Where

$s = \frac{a + b + c}{2}$

Here,

$a = 2$

$b = 3$

$c = 4$

Therefore,

$s = \frac{2 + 3 + 4}{2} = \frac{9}{2} = 4.5$

So,

$a r e a = \sqrt{4.5 \cdot \left(4.5 - 2\right) \cdot \left(4.5 - 3\right) \cdot \left(4.5 - 4\right)}$

$= \sqrt{8.3475}$

$= 2.9 {u}^{2}$

Where $u$, represents the units in this case.