# How do you find the asymptotes for (2x - 4) / (x^2 - 4)?

Apr 26, 2018

$x = - 2$

#### Explanation:

if you factorise :

$\frac{2 \left(x - 2\right)}{\left(x - 2\right) \left(x + 2\right)}$

$x - 2$ cancels

$\frac{2}{x + 2}$

If $x = - 2$ then we will have zero as the denominator so this would give the asymptote