# How do you find the asymptotes for #f(x)=(4x+8)/(x-3)#?

##### 1 Answer

Jan 22, 2016

#### Answer:

vertical asymptote at x = 3 and a horizontal asymptote at y = 4

#### Explanation:

Vertical asymptotes occur when the denominator of the rational

function is 0.

here this would occur when: x - 3 = 0 ie x = 3[Horizontal asymptotes can be found when the degree of the

numerator and the degree of the denominator are equal .]In this question they are both of degree 1 and so equal.

and the asymptote is found by taking the ratio of leading >coefficients

hence y =

# 4/1 =4 #

graph{(4x+8)/(x-3) [-40, 40, -20, 20]}