# How do you find the asymptotes for ln(x-2)?

Oct 8, 2017

$x = 2$

#### Explanation:

The logarithm function (any base) is only defined for positive values, and and asymptote occurs for $x \rightarrow 0$

Thus for ln(x-2) we have an asymptote as $x - 2 \rightarrow 0$, ie when $x = 2$.

We can confirm this graphically:

graph{ln(x-2) [-5, 15, -15, 15]}