How do you find the asymptotes for #ln(x-2)#?

1 Answer
Feb 28, 2018

Answer:

Vertical asymptote at #x=2.#

Explanation:

A logarithmic function has a vertical asymptote at #x=c# where #c# is the value of #x# causes the argument inside the parentheses to become #0.# This is because #log_a(x), ln(x)# do not exist for #x<0.#

For #ln(x-2):#

#x-2=0#

#x=2#

Is the vertical asymptote, as for values less than #x=2, ln(x-2)# doesn't exist.

As for horizontal asymptotes, logarithmic functions don't generally have any (at least in the forms #log_a(x), ln(x).#)