How do you find the asymptotes for #sin^2x#?

1 Answer
Apr 4, 2018

Answer:

vertical asymptotes: none
horizontal asymptotes: none
slant/oblique asymptotes: none

Explanation:

The #sin^{2}x# function is continuous across the entire domain of all real numbers, so there are no vertical asymptotes.

The #sin^{2}x# function oscillates back and forth between all values in it's range of #[0, 1]#, so it doesn't have any horizontal or slant/oblique asymptotes either.