How do you find the asymptotes for #(x+32)/x^2#?

1 Answer
Mar 8, 2016

Answer:

Vertical asymptote: #x=0#
Horizontal asymptote: #y=0#

Explanation:

To find vertical asymptotes, set the denominator of the function equal to #0#.

#x^2=0#

#x=0#

There is a vertical asymptote at #x=0#.

The rule for finding horizontal asymptotes when the degree of the denominator is larger than the numerator, as is the case here, since #2>1#, the horizontal asymptote will be the line #y=0#.

graph{(x+32)/x^2 [-33.14, 31.82, -3.75, 28.74]}