# How do you find the asymptotes for (x+32)/x^2?

Mar 8, 2016

Vertical asymptote: $x = 0$
Horizontal asymptote: $y = 0$

#### Explanation:

To find vertical asymptotes, set the denominator of the function equal to $0$.

${x}^{2} = 0$

$x = 0$

There is a vertical asymptote at $x = 0$.

The rule for finding horizontal asymptotes when the degree of the denominator is larger than the numerator, as is the case here, since $2 > 1$, the horizontal asymptote will be the line $y = 0$.

graph{(x+32)/x^2 [-33.14, 31.82, -3.75, 28.74]}