# How do you find the asymptotes for #(x+32)/x^2#?

##### 1 Answer

Mar 8, 2016

#### Answer:

Vertical asymptote:

Horizontal asymptote:

#### Explanation:

To find **vertical asymptotes**, set the denominator of the function equal to

#x^2=0#

#x=0#

There is a vertical asymptote at

The rule for finding **horizontal asymptotes** when the degree of the denominator is larger than the numerator, as is the case here, since

graph{(x+32)/x^2 [-33.14, 31.82, -3.75, 28.74]}