Question

How do you find the asymptotes for `(x+32)/x^2`?

Answer 1

Vertical asymptote: `x=0`
Horizontal asymptote: `y=0`

Explanation:

To find vertical asymptotes, set the denominator of the function equal to `0`.

`x^2=0`

`x=0`

There is a vertical asymptote at `x=0`.

The rule for finding horizontal asymptotes when the degree of the denominator is larger than the numerator, as is the case here, since `2>1`, the horizontal asymptote will be the line `y=0`.

graph{(x+32)/x^2 [-33.14, 31.82, -3.75, 28.74]}