How do you find the asymptotes for #y=(2x)/(x-3)#?

1 Answer
Feb 18, 2016

Answer:

vertical asymptote at x = 3
horizontal asymptote at y = 2

Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation let the denominator equal zero.

solve : x - 3 = 0 → x = 3

Horizontal asymptotes occur as #lim_(x→±∞) f(x) → 0#

If the degree of the numerator and denominator are equal the equation can be found by taking the ratio of leading coefficients. In this question they are both of degree 1.

hence : y# = 2/1 = 2 #
here is the graph of the function to illustrate them.
graph{2x/(x-3) [-10, 10, -5, 5]}