# How do you find the asymptotes for # y=(x+3)/(2x-8)#?

##### 1 Answer

Explanation is given below

#### Explanation:

For this problem, vertical asymptotes are found by equating the denominator to zero and solving for x.

**Equation of vertical asymptote.**

For horizontal asymptote, check out the degree of numerator and denominator. If the degree of the numerator is same as the degree of denominator.

The Horizontal asymptote is got by dividing the lead coefficients of numerator and denominator.

For example if

Vertical asymptote is got by solving for

The Horizontal asymptote is got by

For our problem

**The horizontal asymptote would be**

**Note:**

*If the degree of the numerator is greater than the degree of denominator then there is no Horizontal Asymptote.*

*If the degree of the denominator is greater than the degree of numerator then #y=0# is the Horizontal Asymptote.*