Question

How do you find the average rate of change of `f(x) = x^2 + 3x - 5`, from x = 0, x = 2?

Answer 1

`5`

Explanation:

The average rate of change over an interval `[a,b]` is

`(f(b)-f(a))/(b-a)`

Thus, the average rate of change of `f(x)=x^2+3x-5` on `[0,2]` is

`(f(2)-f(0))/(2-0)=(5-(-5))/2=5`