Question

How do you find the average rate of change of `y=(2x+1)/(x+2)` over [1,3]?

Answer 1

The average rate of change is `(y_2-y_1)/(x_2-x_1)`. (Yes. It is the same as the slope.)

Explanation:

In this question, `x_1 = 1`, so `y_1 = 1`

ans `x_2 = 3`, so `y_2=7/5`.

`(y_2-y_1)/(x_2-x_1) = (7/5-1)/(3-1) = (2/5)/2=(2/5)/(2/1) = 2/5 * 1/2 = 1/5`