Question

How do you find the axis of symmetry, and the maximum or minimum value of the function `y = x^2 - 4x + 1`?

Answer 1

The axis of symmetry is `x=2` and minimum point is at `(2,-3)`.

Explanation:

`y=x^2-4x+1 or y=(x-2)^2-4+1or y=(x-2)^2-3`.The vertex is at `(2,-3)`.As the sign of `x^2` is +ive, the parabola opens upwards.
The axis of symmetry is `x=2` and minimum point is at `(2,-3)`. graph{x^2-4x+1 [-10, 10, -5, 5]}[Ans]