# How do you find the axis of symmetry, and the maximum or minimum value of the function y=x^2-1?

Mar 6, 2016

Axis of symmetry is $x = 0$
Vertex at $\left(x , y\right) \to \left(0 , - 1\right)$

#### Explanation:

Standard form equation:$y = a {x}^{2} + b x + c$

There is no $b x$ term so the axis of symmetry is at $x = 0$

If the equation had just been $y = {x}^{2}$ the vertex would have been at $\left(x , y\right) \to \left(0 , 0\right)$ but the constant of -1 has dropped this to

$\left(x , y\right) \to \left(0 , - 1\right)$