Question

How do you find the axis of symmetry and vertex point of the function: `y=0.5x^2+4x-2`?

Answer 1

This function has a vertax at `V=(-4,-10)` and an axis of symetry:
`x=-4`

Explanation:

Every parabola `y=ax^2+bx+c` has a vertex at point `V=(p,q)` where:

`p=(-b)/(2a)`

`q` can be calculated as `q=(-Delta)/(4a)` or by substituting the value of `p` to the formula of function.

The line `x=p` is also the axis of symetry.