How do you find the axis of symmetry and vertex point of the function: y=0.5x^2+4x-2?

Sep 29, 2015

This function has a vertax at $V = \left(- 4 , - 10\right)$ and an axis of symetry:
$x = - 4$

Explanation:

Every parabola $y = a {x}^{2} + b x + c$ has a vertex at point $V = \left(p , q\right)$ where:

$p = \frac{- b}{2 a}$

$q$ can be calculated as $q = \frac{- \Delta}{4 a}$ or by substituting the value of $p$ to the formula of function.

The line $x = p$ is also the axis of symetry.