# How do you find the axis of symmetry and vertex point of the function: y = 2x^2 + 24x + 62?

Jun 9, 2018

The Axis of Symmetry occurs at $x = - 6$
The Vertex occurs at $\left(x , y\right) = \left(- 6 , - 10\right)$

#### Explanation:

The axis of symmetry of a quadratic equation is always located at $x = \setminus \frac{- b}{2 a}$ which in this case is equal to $\setminus \frac{- 24}{2 \setminus \cdot 2} = - 6$.

$\setminus \therefore$ Axis of Symmetry occurs at $x = - 6$

The vertex is the point that the function takes at the axis of symmetry.

$\setminus \therefore$ in the case of this problem, the vertex is $\left(- 6 , f \left(- 6\right)\right)$ which is equal to $\left(- 6 , - 10\right)$